A basis for the null space of C A:matrix([1,2,3],[2,4,6]); 1 Give a basis for the null space of \(C={@A@}\), with one vector in each column. Any basis is accepted. Choose the number of columns yourself; use exact fractions.

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]]> 10.1 ansmatrixnullspace_basis(A)8101111 result110PythonCheckeransA{"checker": "basis", "options": {"space": "nullspace"}} =1-1basis-T =0-1basis-F 1ansmatrix([-2,-3],[1,0],[0,1])result10basis-T 2ansmatrix([-3,-2],[0,1],[1,0])result10basis-T 3ansmatrix([-5,-1],[1,-1],[1,1])result10basis-T 4ansmatrix([-4,-3],[2,0],[0,1])result10basis-T 5ansmatrix([-2],[1],[0])result00.1basis-F 6ansmatrix([-2,-4],[1,2],[0,0])result00.1basis-F 7ansmatrix([-2,1],[1,0],[0,0])result00.1basis-F 8ansmatrix([-2,-3,-5],[1,0,1],[0,1,1])result00.1basis-F 9ansmatrix([0,0],[0,0],[0,0])result00.1basis-F