A basis for the null space of B A:matrix([1,0,1],[0,1,1],[1,1,2]); 1 Give a basis for the null space of \(B={@A@}\), with one vector in each column. Any basis is accepted. Choose the number of columns yourself; use exact fractions.

[[input:ans]] [[validation:ans]] [[feedback:result]]

]]> 10.1 ansmatrixnullspace_basis(A)8101111 result110PythonCheckeransA{"checker": "basis", "options": {"space": "nullspace"}} =1-1basis-T =0-1basis-F 1ansmatrix([-1],[-1],[1])result10basis-T 2ansmatrix([2],[2],[-2])result10basis-T 3ansmatrix([0],[0],[0])result00.1basis-F 4ansmatrix([1],[0],[0])result00.1basis-F 5ansmatrix([-1,2],[-1,2],[1,-2])result00.1basis-F