AlgMap-6.4 (corrected teaching copy) Simplify the algebraic expression: \[{@p@}.\] Be sure to leave your answer in the form \(x^y\).

[[input:ans]] [[validation:ans]]

]]> Here we can use the rules of indices, \(c^a\cdot c^b=c^{a+b}\), which apply to algebraic expressions as well as numeric values.

]]> 1 0.1 0 p:(c^a)*(c^b); ta:c^(a+b); [[feedback:prt1]]

]]> \[{@c@}^{@a@}\cdot {@c@}^{@b@} = {@ta@} .\] 0 0 0 *10 dot 1 i cos-1 lang [ 0 {"author":[{"firstName":"Tony","lastName":"Barnard","institution":"","year":"1999"}],"language":["en"],"isPartOf":"STACK Library - Algebra Refresher","license":"cc-sa-4.0","additional":{"UoE":{"Notes":"This is automatically generated metadata."}},"freeform":{}} ans algebraic ta 15 1 0 0 ratsimp 1 1 1 1 1 prt1 1.0000000 0 1 0 EqualComAss ans ta 0 = 1.0000000 -1 1-0-T = 0.0000000 1 1-0-F 1 AlgEquiv ans ta 0 = 0.0000000 -1 1-1-T Your answer is equivalent to the correct answer but you haven't fully simplified.

]]> = 0.0000000 -1 1-1-F 1 ans ta prt1 1.0000000 0.0000000 1-0-T 2 ans p prt1 0.0000000 0.1000000 1-1-T 3 ans c^(a*b) prt1 0.0000000 0.1000000 1-1-F