AlgMap-8.5 Simplify the following algebraic fraction: \[ \frac{@b-a@}{@a-b@}. \]
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]]> The first step should be to take a factor of \({-1}\) from the numerator of the fraction so that: \[ \frac{@b-a@}{@a-b@} = \frac{-(a-b)}{@a-b@}. \] Now, it is clear that the factor \((a-b)\) can be cancelled from the numerator and the denominator of the fraction leaving {@ta@}.

]]> 1 0.1 0 ta:-1; [[feedback:prt1]]

]]> \[ \frac{@b-a@}{@a-b@} = {@ta@}. \] 1 0 0 *10 dot 1 i cos-1 lang [ 0 {"author":[{"firstName":"Tony","lastName":"Barnard","institution":"","year":"1999"}],"language":["en"],"isPartOf":"STACK Library - Algebra Refresher","license":"cc-sa-4.0","additional":{"UoE":{"Notes":"This is automatically generated metadata."}},"freeform":{}} ans algebraic ta 15 1 0 0 1 0 1 1 1 prt1 1.0000000 0 1 0 EqualComAss ans ta 0 = 1.0000000 -1 1-0-T = 0.0000000 1 1-0-F 1 AlgEquiv ans ta 0 = 0.0000000 -1 1-1-T Your answer is algebraically equivalent to the correct answer but you haven't simplified fully.

]]> = 0.0000000 2 1-1-F 2 AlgEquiv ans 1 0 = 0.0000000 -1 1-2-T You seemed to have dropped a minus sign! Your answer should be negative.

]]> = 0.0000000 3 1-2-F 3 AlgEquiv ans 0 0 = 0.0000000 -1 1-3-T Remember that \(\frac{x}{x} = 1\) and not equal to zero.

]]> = 0.0000000 -1 1-3-F 1 ans ta prt1 1.0000000 0.0000000 1-0-T 2 ans (b-a)/(a-b) prt1 0.0000000 0.1000000 1-1-T 3 ans 1 prt1 0.0000000 0.1000000 1-2-T 4 ans 0 prt1 0.0000000 0.1000000 1-3-T