AlgMap-3.1 Express the following, as a single fraction: \[{@a/b@}+{@c/d@}.\]

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Leave your answer in it's lowest terms in the form \(\frac{a}{b}\).

]]> In this case the denominators of the fractions are equal so you simply add the numerators to obtain the numerator and the denominator stays the same.

The general rule is: \[\frac{a}{b} + \frac{c}{b} = \frac{a+c}{b} \] In this exmaple: \[{@a/b@}+{@c/d@} = \frac{{@a@}+{@c@}}{@b@} = {@ta@}.\]

]]> 1 0.1 0 2026010500 simp:true; b:rand(5)+3; a:b-1; d:b; c:d+1; ta:(a/b)+(c/d); lcm:lcm(b,d); simp:false; [[feedback:prt1]]

]]> \[{@a/b@}+{@c/d@} = {@ta@}.\] 0 0 0 *10 dot 1 i cos-1 lang [ 0 {"author":[{"firstName":"Tony","lastName":"Barnard","institution":"","year":"1999"}],"language":["en"],"isPartOf":"STACK Library - Algebra Refresher","license":"cc-sa-4.0","additional":{"UoE":{"Notes":"This is automatically generated metadata."}},"freeform":{}} ans algebraic ta 15 1 0 0 1 0 1 1 1 prt1 1.0000000 0 1 0 Correct answers EqualComAssRules ans ta [ID_TRANS] 0 = 1 -1 prt1-1-T = 0 1 prt1-1-F 1 AlgEquiv ans ta 0 = 0 -1 prt1-2-T Simplify the fraction fully into the form \(\frac{a}{b}\) and leave in it's lowest terms.

]]> = 0 2 prt1-2-F 2 Naive adding of fractions/mediant AlgEquiv ans (a+c)/(b+d) 0 = 0 -1 prt1-3-T Remember that the first step in adding fractions is to make both denominators equal. It is not simply adding the numerators and the denominators.

]]> = 0 -1 prt1-3-F 1329293196 708806052 2090926622 1621878102 944404612 1 ans ta prt1 1.0000000 0.0000000 prt1-1-T 2 ans (a+c)/(b+d) prt1 0.0000000 0.1000000 prt1-3-T 3 ans a/b+c/d prt1 0.0000000 0.1000000 prt1-2-T 4 Literal a/b ans 2/1 prt1 1.0000000 0.0000000 prt1-1-T 5 Wrong answer ans 3/2 prt1 0.0000000 prt1-3-F